Introduction

7

Time series algorithms are extensively used for analyzing and forecasting time-based data. These algorithms are built on underlying statistical assumptions. In this guide, you will learn the underlying statistical assumptions and the basic time series algorithms and how to implement them in R.

Let's begin with the problem statement and data.

Unemployment is a major socio-economic and political issue for any country, and managing it is a primary task for any government. In this guide, you'll forecast unemployment levels for a twelve-month period.

The data used in this guide is from US economic time series data available from http://research.stlouisfed.org/fred2h. The data contains 574 rows and 6 variables, as described below:

`date`

: the first date of every month starting from January 1968`psavert`

: personal savings rate`pce`

: personal consumption expenditures, in billions of dollars`uempmed`

: median duration of unemployment, in weeks`pop`

: total population, in thousands`unemploy`

: number of unemployed in thousands (dependent variable)

The focus will be on the `date`

and `unemploy`

variables, as the area of interest is univariate time-series forecasting.

The lines of code below load the required libraries and the data.

`1 2 3 4 5 6 7 8 9`

`library(readr) library(ggplot2) library(forecast) library(fpp2) library(TTR) library(dplyr) dat <- read_csv("timeseriesdata.csv") glimpse(dat)`

{r}

Output:

`1 2 3 4 5 6 7 8 9`

`Observations: 564 Variables: 7 $ date <chr> "01-01-1968", "01-02-1968", "01-03-1968", "01-04-1968", "01-0... $ pce <dbl> 531.5, 534.2, 544.9, 544.6, 550.4, 556.8, 563.8, 567.6, 568.8... $ pop <int> 199808, 199920, 200056, 200208, 200361, 200536, 200706, 20089... $ psavert <dbl> 11.7, 12.2, 11.6, 12.2, 12.0, 11.6, 10.6, 10.4, 10.4, 10.6, 1... $ uempmed <dbl> 5.1, 4.5, 4.1, 4.6, 4.4, 4.4, 4.5, 4.2, 4.6, 4.8, 4.4, 4.4, 4... $ unemploy <int> 2878, 3001, 2877, 2709, 2740, 2938, 2883, 2768, 2686, 2689, 2... $ Class <chr> "Train", "Train", "Train", "Train", "Train", "Train", "Train"...`

For model validation, create the training and test datasets.

`1 2 3 4`

`dat_train = subset(dat, Class == 'Train') dat_test = subset(dat, Class == 'Test') nrow(dat_train); nrow(dat_test)`

{r}

Output:

`1 2`

`[1] 552 [1] 12`

In order to run forecasting models in R, you'll have to convert the data into a time series object, which is done in the *first line of code* below. The `start`

and `end`

arguments specify the time of the first and the last observations, respectively. The argument `frequency`

specifies the number of observations per unit of time.

You'll also need a utility function for calculating the *mean absolute percentage error (MAPE)*, which will be used to evaluate the performance of the forecasting models. The lower the MAPE value, the better the forecasting model performance. This is done in the second to fourth lines of code.

`1 2 3 4 5 6 7`

`dat_ts <- ts(dat_train[, 6], start = c(1968, 1), end = c(2013, 12), frequency = 12) #lines 2 to 4 mape <- function(actual,pred){ mape <- mean(abs((actual - pred)/actual))*100 return (mape) }`

{r}

With the data and the MAPE function prepared, you are ready to move to the forecasting techniques in the subsequent sections. However, before moving to forecasting, it's important to understand the important statistical concepts of white noise and stationarity in time series.

A *white noise* series is a time series that is purely random, and the variables are independent and identically distributed with a mean of zero. This means that the observations have the same variance and there is no autocorrelation. The lines of code below set the seed for reproducibility and generate the plot of the series.

`1 2 3`

`set.seed(100) wnoise = ts(dat_ts) autoplot(wnoise)`

{r}

Output:

There seems to be information in the data, and it is not a purely random series. In a white noise series, it is expected that the autocorrelation will be zero. To visualize this, use the `ggAcf()`

function, as shown in the code below.

`1`

`ggAcf(wnoise) + ggtitle("ACF Plot for white noise")`

{r}

Output:

If this is a white noise time series, 95 percent or more of the lags will lie between the bounds on a graph of the ACF. This is shown with the blue dashed lines above. In this case, you can see that majority of the lines are above the blue dashed line, which indicates that this is not a white noise time series.

Instead of the visualization above, you can also use the *Ljung-Box test* to find out if the series is a white noise series. A test of significance, indicated by a small p-value, confirms that the series is probably not white noise. The code below performs this test.

`1`

`Box.test(dat_ts, lag = 50, fitdf = 0, type = "Lj")`

{r}

Output:

`1 2 3 4`

`Box-Ljung test data: dat_ts X-squared = 10051, df = 50, p-value < 2.2e-16`

The p-value is less than 0.05, indicating that the series is not a white noise series. That means there is information in the data that can be used to forecast future values.

One of the popular time series algorithm is the Auto Regressive Integrated Moving Average (ARIMA), which is defined for stationary series. A *stationary* series is one where the properties do not change over time. In simple terms, the level and variance of the series stays roughly constant over time. You can visualize the series with the code below.

`1`

`plot.ts(dat_ts)`

{r}

Output:

The above plot shows that the series is not stationary, which is a required for building an ARIMA model. To make the series stationary, perform the statistical operation *differencing* using the `diff()`

function in R.
This is done below.

`1 2`

`dat_tsdiff1 <- diff(dat_ts, differences=1) plot.ts(dat_tsdiff1)`

{r}

Output:

The above plot shows that the time series of first differences does appear to be roughly stationary in mean and variance. Thus, it appears that we have an ARIMA(p,1,q) model. Having understood the basic statistical concepts of time series, you'll now build some time series forecasting models.

In exponential smoothing methods, forecasts are produced using weighted averages of past observations, with the weights decaying exponentially as the observations get older. The value of the smoothing parameter for the level is decided by the parameter `alpha`

.
The code below creates the simple exponential smoothing model and prints the summary.

`1 2`

`se_model <- ses(dat_ts, h = 12) summary(se_model)`

{r}

Output:

`1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37`

`Forecast method: Simple exponential smoothing Model Information: Simple exponential smoothing Call: ses(y = dat_ts, h = 12) Smoothing parameters: alpha = 0.9999 Initial states: l = 2849.6943 sigma: 215.1798 AIC AICc BIC 9419.182 9419.226 9432.123 Error measures: ME RMSE MAE MPE MAPE MASE ACF1 Training set 13.63606 214.7896 160.8971 0.1946177 2.146727 0.1687594 0.2017391 Forecasts: Point Forecast Lo 80 Hi 80 Lo 95 Hi 95 Jan 2014 10376.04 10100.280 10651.81 9954.299 10797.79 Feb 2014 10376.04 9986.074 10766.01 9779.637 10972.45 Mar 2014 10376.04 9898.438 10853.65 9645.609 11106.48 Apr 2014 10376.04 9824.557 10927.53 9532.618 11219.47 May 2014 10376.04 9759.466 10992.62 9433.070 11319.02 Jun 2014 10376.04 9700.619 11051.47 9343.071 11409.02 Jul 2014 10376.04 9646.504 11105.58 9260.308 11491.78 Aug 2014 10376.04 9596.134 11155.95 9183.274 11568.81 Sep 2014 10376.04 9548.826 11203.26 9110.923 11641.17 Oct 2014 10376.04 9504.080 11248.01 9042.490 11709.60 Nov 2014 10376.04 9461.521 11290.57 8977.402 11774.69 Dec 2014 10376.04 9420.857 11331.23 8915.212 11836.88`

The output above shows that the simple exponential smoothing has the same value for all the forecasts. Because the alpha value is close to 1, the forecasts are closer to the most recent observations. Now, evaluate the model performance on the test data.

The code below stores the output of the model in a data frame and adds a new variable, `simplexp`

, in the test data which contains the forecasted value from the simple exponential model. Finally, the `mape`

function is used to produce the MAPE error on the test data, which comes out to be 8.5 percent.

`1 2 3`

`df_fc = as.data.frame(se_model) dat_test$simplexp = df_fc$`Point Forecast` mape(dat_test$unemploy, dat_test$simplexp)`

{r}

Output:

`1`

`[1] 8.486869`

This is an extension of the simple exponential smoothing method that takes into account the trend component while generating forecasts. This method involves two smoothing equations, one for the level and one for the trend component.

The code below creates the holt's model and prints the summary.

`1 2`

`holt_model <- holt(dat_ts, h = 12) summary(holt_model)`

{r}

Output:

`1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40`

`Forecast method: Holt's method Model Information: Holt's method Call: holt(y = dat_ts, h = 12) Smoothing parameters: alpha = 0.8743 beta = 0.2251 Initial states: l = 2941.2241 b = -0.9146 sigma: 200.7121 AIC AICc BIC 9344.330 9344.440 9365.898 Error measures: ME RMSE MAE MPE MAPE MASE ACF1 Training set -1.775468 199.9836 152.9176 0.04058417 2.056684 0.16039 -0.001011626 Forecasts: Point Forecast Lo 80 Hi 80 Lo 95 Hi 95 Jan 2014 10194.656 9937.433 10451.879 9801.267 10588.04 Feb 2014 9973.102 9590.814 10355.390 9388.443 10557.76 Mar 2014 9751.549 9239.463 10263.634 8968.381 10534.72 Apr 2014 9529.995 8881.048 10178.943 8537.515 10522.48 May 2014 9308.442 8514.997 10101.887 8094.972 10521.91 Jun 2014 9086.888 8141.265 10032.512 7640.682 10533.10 Jul 2014 8865.335 7759.990 9970.680 7174.856 10555.81 Aug 2014 8643.782 7371.378 9916.185 6697.808 10589.76 Sep 2014 8422.228 6975.652 9868.804 6209.881 10634.58 Oct 2014 8200.675 6573.036 9828.313 5711.416 10689.93 Nov 2014 7979.121 6163.744 9794.498 5202.741 10755.50 Dec 2014 7757.568 5747.979 9767.157 4684.167 10830.97`

The output above shows that the MAPE for the training data is 2.1 percent. Evaluate the model performance on the test data using the lines of code below. The MAPE error on the test data comes out to be 6.6 percent, which is an improvement over the previous models.

`1 2 3`

`df_holt = as.data.frame(holt_model) dat_test$holt = df_holt$`Point Forecast` mape(dat_test$unemploy, dat_test$holt)`

{r}

Output:

`1`

`[1] 6.597904`

While exponential smoothing models are based on a description of the trend and seasonality, ARIMA models aim to describe the auto-correlations in the data.
The `auto.arima()`

function in R is used to build an ARIMA model. The code below creates the model and prints the summary.

`1 2`

`arima_model <- auto.arima(dat_ts) summary(arima_model)`

{r}

Output:

`1 2 3 4 5 6 7 8 9 10 11 12 13 14`

`Series: dat_ts ARIMA(1,1,2)(0,0,2)[12] Coefficients: ar1 ma1 ma2 sma1 sma2 0.9277 -0.8832 0.1526 -0.2287 -0.2401 s.e. 0.0248 0.0495 0.0446 0.0431 0.0392 sigma^2 estimated as 35701: log likelihood=-3668.8 AIC=7349.59 AICc=7349.75 BIC=7375.46 Training set error measures: ME RMSE MAE MPE MAPE MASE ACF1 Training set 6.377816 187.9162 143.4292 0.1084702 1.940315 0.150438 0.005512865`

The output above shows that the MAPE for the training data is 1.94 percent. The next step is to evaluate the model performance on the test data, which is done in the lines of code below. The MAPE error on the test data comes out to be 2.1 percent, which is an improvement over all the previous models.

`1 2 3 4`

`fore_arima = forecast::forecast(arima_model, h=12) df_arima = as.data.frame(fore_arima) dat_test$arima = df_arima$`Point Forecast` mape(dat_test$unemploy, dat_test$arima) ## 2.1%`

{r}

Output:

`1`

`[1] 2.063779`

In this guide, you learned about the underlying statistical concepts of white noise and stationarity in time series data. You also learned how to implement basic time series forecasting models using R. The performance of the models on the test data is summarized below:

- Simple Exponential Smoothing: MAPE of 8.5 percent
- Holt's Trend Method: MAPE of 6.6 percent
- ARIMA: MAPE of 2.1 percent

The Simple Exponential Smoothing model did well to achieve a lower MAPE of 8.5 percent. The other two models outperformed it by producing an even lower MAPE. The ARIMA model emerged as the winner based on its lowest MAPE of 2.1 percent.

7